Showing posts with label solids. Show all posts
Showing posts with label solids. Show all posts

Tuesday, 7 February 2012

CE 1255 Highway Engineering QB


CE 1255 Highway Engineering
1. Define central road fund?
On the recornmendation of Jayhawker committee, central
Road fund came into existence on 1st march 1929, Upon the authority
of a resolution adopted by the Indian legislature.

2. Define National Highway Act 1956?
In 1956, National Highway act was passed declaring the
National Highways and empowering the central Govt to declare any
other highway to be NH. This act came into force with effect from
15th April 1957.

3. Explain CRRI?
CRRI- The central Road Research Institute Delhi in 1950
It is an organ of the council of scientific and industrial research, and
in function include.

4. Write Short notes on Highway Research Board?
This board was set up by I.R.C in 1973 to give proper
direction and guidance to road research work in India.

5. What are classified roads in Nagpur plan?
1. National Highways (NH)
2. State Highways (SH)
3. District Roads:
(1) Major district Roads
(2) Other district Roads
4. Village roads.

Saturday, 4 February 2012

ADVANCED STRENGTH OF MATERIALS important question

Unit:1 Energy principles
Part : B
6 marks
1.Find the deflection of a simply supported carrying a concentrated load at mid span. Assume uniform
flexural rigidly.
Mx= x
=
Deflection= dx
= dx
=
= [ ]
= [wx( )3]
=
2. Find the deflection at free end of the cantilever of length ’l’ carrying a u dl w/l over the whole span
P is a imaginary load at end B
Mx=-px- =-x
Deflection= dx
=
=
P=0
=
= [ ]
=
3. Define unit load method and explain it.
The principle of virtual work is based on the conservation of energy for a structure which implies loads
is equal to the internal energy stored in the structure
Ue=Ui
For beam, deflection =
In general,the principle of virtual work and energy states ΣP Δ = Σfδ
Work of External loads=Work of internal forces.

ADVANCED STRENGTH OF MATERIALS UNIT :5


UNIT : 5 Advanced topics in bending of stress
1) What are the assumptions made in the analysis of curved bar?
1. Plane section remains plain during bending.
2. The material obeys Hooke’s law.
3. Radial strain is negligible.
4. Each layer is free to expand or contract, independently of the layer above or below it.
2) Define unsymmetrical bending
If the plane of loading or that of bending does not lie in (or parallel to) a plane that contains the principal
centroidal axis of cross section, the bending is called unsymmetrical bending.
3) What are the reasons for unsymmetrical bending?
1. The section is symmetrical but the load line is inclined to both the principal axis.
2. The section itself is unsymmetrical and the load line is along the centroidal axis.
4) What is shear centre or angle of twist?
The shear centre for any transverse section of the beam is the point of intersection of the bending axis
and the plane of the transverse section.
5) Who postulated the theory of curved beam?
Winkler-bach postulated the theory of curved beam.
6) Define Principal moment of inertia
The perpendicular axis about which the product of inertia is zero is called Principal axes and the
moment of inertia with respect to this axis is called Principal moment of inertia.

ADVANCED STRENGTH OF MATERIALS UNIT :4


UNIT :4 state of stress in 3 dimension
1) What are the types of failure?
The 2 types of failure are;
I. Brittle failure
II. Ductile failure
2) Define Brittle failure
Failure of a material represents direct separation of particles from each other, accompanied
by considerable deformation is known as Brittle failure.
3) Define ductile failure
Slipping of a material accompanied, by considerable plastic deformations is known as ductile
failure.
4) Define tensor
State of a stress at a point is defined by three components on each of the three mutually
perpendicular axis in mathematical terminology is called tensor.
5) List out the theories of failure
 Maximum principal stress theory(Rankine’s theory)
 Maximum principal strain theory(St.Venant’s theory)
 Maximum shear stress theory(Tresca’s & guest theory)
 Maximum shear strain energy theory(Von-Mises-Hencky theory)
 Maximum strain energy theory(Haigh’s theory)
6) Define Maximum principal stress theory (Rankine’s theory)
According to this theory, the failure of a material will occur when the maximum principal
tensile stress (σ1) in the complex system reaches the value of the maximum stress (σ t*) at the elastic
limit in simple tension or the minimum principal stress (i.e., the maximum principal compressive stress)
reaches the value of the maximum stress at the elastic limit in simple compression..
σ1= σ t*
7) Define Maximum principal strain theory (St.Venant’s theory)
According to this theory, the failure of a material will occur when the maximum principal strain
(e1) reaches the strain due to the yield stress in simple tension (σ t*/E).
e1= σ t*/E
In 3D e1= [σ1-μ (σ2+σ3)] = σ t*/E
In 2D e1= [σ1-μσ2] = σ t*/E
8) Define Maximum shear stress theory (Tresca’s & guest theory)
According to this theory, the failure of a material will occur when the maximum shear stress in
the body will reaches the value of Maximum shear stress in simple tension at the elastic limit.
In 3D (σ1- σ3) = σ t*
In 2D σ1 = σ t*
9) Define Maximum shear strain energy theory (Von-Mises-Hencky theory)
According to this theory, the failure of a material will occur when the total shear strain energy
per unit volume in the stressed material reaches a value equal to the shear strain energy per unit
volume at the elastic limit in simple tensile test.
In 3D shear strain energy due to distortion U = (1/12C) [(σ1- σ2) ^2+ (σ2- σ3) ^2+ (σ3- σ1) ^2]
In 3D shear strain energy due to simple tension U = σ t*^2\6C
U= (1/6C) [(σ1- σ2) ^2+ (σ2- σ3) ^2+ (σ3- σ1) ^2] = σ t*^2\6C
In 2D shear strain energy due to simple tension
U= (1/6C) [(σ1- σ2) ^2+ (σ2) ^2+ (σ1) ^2] = σ t*^2\6C
10) Define Maximum strain energy theory (Haigh’s theory)
According to this theory, the failure of a material will occur when the total strain energy per
unit volume in the stressed material reaches the strain energy per unit volume of the material at the
elastic limit in simple tensile test.
In 3D shear strain energy due to deformation
U= (1/2E) [σ1^2+ σ2^2+ σ3^2+-2μ (σ1σ2 +σ2σ3 +σ3 σ1)]
In 3D shear strain energy due to simple tension U= σ t*^2\2E
U= [σ1^2+ σ2^2+ σ3^2+-2μ (σ1σ2 +σ2σ3 +σ3 σ1)] = σ t*^2
In 2D U= [σ1^2+ σ2^2 -2μ (σ1σ2)] = σ t*^2
11) Write the limitations of Maximum principal stress theory (Rankine’s theory)
• This theory disregards the effect of other principal stresses & effect of shearing
stresses on other planes through the planes through the element.
• Material in tension test piece along 45º to the axis of the test piece, where normal
stress is neither maximum nor minimum, but the shear stress is maximum.
• Failure is not brittle but cleavage failure.
12) Write the limitations of shear stress theory (Tresca’s & guest theory)
This theory does not give accurate results for the state of stress of pure shear in which the
maximum amount of shear is developed (in torsion test).
13) Write the limitations of Maximum shear strain energy theory (Von-Mises-Hencky theory)
This theory cannot be applied to materials under hydro static pressure
14) Write the limitations Maximum strain energy theory (Haigh’s theory)
This theory does not apply to brittle materials for which elastic limit in tension and
compression is quite different.
15) Define strain Rosette
Linear strains are measured in all direction by strain gauges known as strain Rosette.
16) Define Plasticity ellipse
The graphical surface of a maximum shear strain energy theory (Von-Mises-Hencky theory) is
a straight circular cylinder.
[σ1^2+ σ2^2 -σ1σ2] = σ t*^2, which is called Plasticity ellipse.
17) Define Octahedral Plane
The plane which is equally inclined to the three axes of reference is called Octahedral Plane.
18) Define Octahedral Stresses
The normal and shear stress acting on the Octahedral Plane (The plane which is equally
inclined to the three axes of reference) is known as Octahedral Stresses.
19) Define volumetric strain per unit volume
Volumetric strain per unit volume is defined as the ratio of change in volume of a material to
its unit volume.
ev = ex +ey +ez
20) What are residual Stresses?
Maximum principal stress and Maximum shear stress are collectively known as residual
Stresses.

ADVANCED STRENGTH OF MATERIALS UNIT :2


UNIT : 2
Indeterminate Beams
1. What do you mean by propped cantilevers?
Propped cantilevers means cantilevers supported on a vertical supported at a
suitable point.
2. How will you find the reaction at the prop?
The reaction of the prop is calculated by equating the down ward deflection due to
load at the point of prop to the upward deflection due in prop reaction.
3. What do you mean by a fixed beam?
A beam whose both ends are fixed is known as fixed beam.
4. What do you mean by a continuous beam?
A beam which is supported on more than two supports is known as a continuous
beam.
5. What is the advantage of fixed beam:
a. The beam is more stable and stronger
b. The slope at both ends of a fixed beam is Zero
c. The fixed beam is subjected to a lesser maximum bending moment
d. The maximum deflection of a fixed beam is less than that of a simply supported
beam.
6. Find an expression for the deflection for a fixed beam carrying a udl throughout the span.
Y=wl^4/192EI
7. Find an expression for deflection for a fixed beam carrying a point load at the centre.
Y=wl^4/384EI

CE 2252 – STRENGTH OF MATERIALS question bank

UNIT – I

1. Derive relation for strain energy due to shear.

2. State Maxwell’s reciprocal theorem.

3. What do you mean by unsymmetrical bending?

4. Define the term Poisson’s ratio and Bulk modulus.

5. Explain the effect of change of temperature in a composite bar.

6. State Castigliano’s first theorem.

7. What is meant by Strain energy?


UNIT – II

1. Derive a relation fro prop reaction for a simply supported beam with uniformly  
    distributed load and propped t the centre.

2 A Steel fixed beam AB of span 6 m is 60 mm wide and 100 mm deep. The support B
    sinks down by 6 mm. Fine the fixing moments at A and B. Take E = 200 GPa.

3. Sketch the bending moment diagram of a cantilever beam subjected o udl over the
      entire span.

4. The section modulus w.r.t.x-axis of a rectangle of width ‘b’ and depth ‘d’ is --------
       and in case of circle, the section modulus is--------.

5. What is meant by point of contraflexure?

6. A cantilever beam 4 m long carries a load of 20 kN at its free end. Calculate the shear
    force and Bending moment at the fixed end.
    
7. Write the equation giving maximum deflection in case of a simply supported beam
     subjected to udl over the entire span.



UNIT – III


1. Discuss the effect of crippling load (Pc) obtained by Eulers formula on Rankine’s
    formula for short columns.

2. Differentiate a thin cylinder and a thick cylinder with respect to hoop stress.

3. Express the strength of a solid shaft.

4. Give the expression for finding deflection of closely coiled helical spring.

5. Give the equivalent length of a column for any two end conditions.

6. A boiler of 800 mm diameter is made up of 10 mm thick plates. If the boiler is
      subjected to an internal pressure of 2.5 MPa, determine circumferential and
      longitudinal stress.

7. Write down Rankine-Gordon formula for eccentrically loaded columns.

8. Define : Middle Third Rule.


UNIT – IV


1.What do you mean by triaxial state of stress.

2. Define principal planes and principal stresses.

3. What is meant by principal plane?

4. Find the principal stresses if the normal stresses sx and sy and shear stess t act at a
    point?


UNIT – V

1. State any four assumptions made in the analysis of stresses in curved bars.

2. What do you mean by unsymmetrical bending.

3. When will you use the simple flexure formula for curved beams?

4. State the assumptions in Winkler – Bach Analysis

5. What are the reasons for unsymmetrical bending?

6. What are the assumptions made in Winkler – Bach theory?


SIXTEEN – MARK QUESTIONS


UNIT – I

1.  A simply supported beam of span “l” carries an uniformly distributed load of W per
     unit length over the entire span. Using Castigliano’s theorem determine                 (16)

(i)                 The mid-span deflection of the beam
(ii)               The slope at the left support.

2.  A simply supported beam of span 8 m carries two concentrated loads of 20 kN and 30 
     kN at 3 m and 6 m from left support. Calculate the deflection at the centre by strain  
     energy principle.                                                                                                         (16)

3.    The external diameter of a hollow shaft is twice the internal diameter. It is subjected  
         to pure torque and it attains a maximum shear stress ‘τ’. Show that the strain energy  
         stored per unit volume of the shaft is 5 τ2 / 16C. Such a shaft is required to transmit
         5400 kw at 110 r.p.m. with uniform torque, the maximum stress not exceeding 84
         MN / m2. Determine,

(i)                    The shaft diameter                                                                                              (8)
(ii)                  The strain energy stored per m3. Take C = 90 GN / m2.                                    (8)


4. Using Castigliano’s theorem, determine the deflection of the free end of the cantilever
      beam shown in fig. A is fixed and B is free end.  Take EI = 4.9 MNm2.                 (16)


UNIT – II

1. A fixed beam of span 8 m carries an udl of 2 kN/m over a length of 4 m from the left
    support and a concentrated load of 10 kN at a distance of 6m from the left support.
    Find the fixed end moments and draw the B.M. and S.F. diagrams.                          (16)

2. A propped cantilever of span of 6 m having the prop at the end is subjected two
    concentrated loads of 15 kN and 30kN at one third points respectively from left fixed
    end support. Draw SFD and BMD with salient points.                                              (16)


3.   A fixed beam of 8 m span carries a uniformly distributed load of 40 kN/m run over
        4 m length starting from left end and a concentrated load of 80 kN at a distance of
        6 m from the left end. Find

(i)                  Moments at the supports.                                                                                  (12)
(ii)               Deflection at the centre of the beam.                                                                   (4)

        Take EI = 15000 kNm2.                                         

4.   A cantilever AB of span 6 m is fixed at the end ‘A’ and propped at the end B. It
        carries a point load of 50 kN at the mid span. Level of the prop is the same as that of   
        the fixed end.                                                                                                           

(i)                 Determine reaction at the prop.                                                                           (12)
(ii)               Draw the S.F. and B.M. diagrams.                                                                       (4)


UNIT – III


1. (i)  Derive the Lame’s equations for thick cylinder.                                                   (12)

    (ii) A thick cylinder has diameter 1.2 m and thickness 100 mm is subjected to an
          internal fluid pressure 15 N/mm2. Sketch the hoop stress distribution.                (4)

2.  (i)  Derive the formula to find the crippling load in a column of length ‘l’ hinged at
           both ends.                                                                                                             (12)

     (ii)  Differentiate between thin and thick cylinders.                                                   (4)

3.   Derive Euler’s crippling load for the following cases :

(i)                  Both ends hinged.                                                                                                (8)
(ii)               One end is fixed and other end free.                                                                     (8)


4.   A column with one end hinged and other end fixed has a length of 5 m and a hollow 
        circular cross-section of outer dia 100 mm and wall thickness 10 mm. If E = 1.60 x
        105 N/mm2 and crushing stress σc = 350 N/ mm2, find the load that the column may
        carry with a factor of safety of 2.5 according to Euler theory and Rankine – Gordon
        theory.                                                                                                                      (16)


UNIT – IV


1.   The state of stress at a certain point in a strained material is shown in Fig. Calculate
     (i) principal stresses  (ii) inclination of the principal planes  (iii) Maximum shear stress
     and its plane.                                                                                                               (16)




2.  Explain the following:                                                                                               (16)

(i)                  Maximum principal stress theory
(ii)               Maximum principal strain theory
(iii)             Maximum strain energy theory and
(iv)             Distortion energy theory.

3.   Derive the expressions for Energy of distortion and Energy of dilatation?           (16)


4.   Determine the principal moments of inertia for an angle section 80 mm x 80 mm x
        10 mm.                                                                                                                     (16)




UNIT – V


1.   Determine the horizontal and vertical deflection of the end B of the thin curved beam
      shown in fig. Take E = 200 GN/m2, width and thickness of the beam 10 mm and 5
      mm respectively. P = 2 N.                                                                                         (16)


2.  (i)  Briefly explain how the Winkler – Bach theory shall be used to determine the
             stresses in a curved beam.                                                                                    (8)

       (ii) Write short notes on:                                                                                            (8)
  
1.       Fatigue and fracture
2.      Stress concentration.







3.  A curved bar is formed of a tube of 120 mm outside diameter and 7.5 mm thickness.
      The centre line of this beam is a circular arc of radius 225 mm. A bending moment of  
      3 kNm tending to increase curvature of the bar is applied. Calculate the maximum
      tensile and compressive stresses set up in the bar.                                                    (16)


4.   Two mutually perpendicular planes of an element of a material are subjected to
      direct stresses of 10.5 MN/m2 (tensile); and 3.5 MN/m2 (compressive) and shear
      stress of 7 MN/m2. Find,

(i)                 The magnitude and direction of principal stresses.                                             (12)
(ii)               The magnitude of the normal and shear stresses on a plane on which the shear stress is maximum.                                                                                            (4)












------------












Friday, 3 February 2012

machanics of solids important question


Part -B
1. A rectangular block of material is subjected to a tensile stress of 110 N/mm2 on one
plane and a tensile stress of 47 N/mm2 on the plane at right angle to the former.
Each of the above stress is accompanied by a shear stress of 63 N/mm2 Find (i)
The direction and magnitude of each of the principal stress (ii) Magnitude of
greatest shear stress.
2. At a point in a strained material, the principal stresses are100 N/mm2 (T) and 40
N/mm2 (C). Determine the resultant stress in magnitude and direction in a plane
inclined at 600 to the axis of major principal stress. What is the maximum intensity
of shear stress in the material at the point?
3. A cantilever truss is show in fig. Find the forces in the members of the truss by the
method of joint.
5 KN 10 KN
Error!
1.5m 3m
600
3m
4. A truss of span 9m is loaded as shown in fig. Find the reaction and forces in the
members marked 1, 2, and 3 by using method of section.
1
2 4m
3
3m 3m 3m
5. A thin cylindrical shell 3 m long has 1m internal diameter and 15 mm metal
thickness. Calculate the circumferential and longitudinal stresses induced and also
the change in the dimensions of the shell, if it is subjected to an internal pressure of
1.5 N/mm2 Take E = 2x105 N/mm2 and poison’s ratio =0.3. Also calculate change in
volume.
6. A closed cylindrical vessel made of steel plates 4 mm thick with plane ends, carries
fluid under pressure of 3 N/mm2 The diameter of the cylinder is 25cm and length is
75 cm. Calculate the longitudinal and hoop stresses in the cylinder wall and
determine the change in diameter, length and Volume of the cylinder. Take E =
2.1x105 N/mm2 and 1/m = 0.286.
7. Derive double integration method for cantilever beam concentrated load at free end.
8. A 2m long cantilever made of steel tube of section 150 mm external diameter and
10mm thick is loaded as show in fig If E=200 GN/m2 calculate (1) The value of W
so that the maximum bending stress is 150 MN/m2 (2) The maximum deflection for
the loading.
2W W
Error!
a = 0.5m
l = 2m
9. Determine the diameter of a solid shaft which will transmit 300 KN at 250 rpm. The
maximum shear stress should not exceed 30 N/mm2 and twist should not be more
than 10 in a shaft length 2m. Take modulus of rigidity = 1x 105N/mm2.
10. The stiffness of the closed coil helical spring at mean diameter 20 cm is made of 3
cm diameter rod and has 16 turns. A weight of 3 KN is dropped on this spring. Find
the height by which the weight should be dropped before striking the spring so that
the spring may be compressed by 18 cm. Take C= 8x104 N/mm2.
11. A compound tube consist of steel tube 140mm internal diameter and 160mm
external diameter and an outer brass tube 160mm internal diameter and 180mm
external diameter. The two tubes are of same length. The compound tube carries an
axial load of 900 KN. Find the stresses and the load carried by each tube and the
amount it shortens. Length of each tube is 140mm. Take E for steel as 2 x 105
N/mm2.
12. A rectangle block of material is subjected to a tensile stress of 110 N/mm2 on one
plane and a tensile stress of 47 N/mm2 on the plane at right angles to the former.
Each of the above stress is accompanied by shear stress of 63 N/mm2. Find (i) the
direction and magnitude of each of the principal stress (ii) magnitude of greatest
shear stress.
13. . At a point in a strained material, the principal stresses are 100 N/mm2 (T) and 40
N/mm2 (C) Determine the direction and magnitude in a plane inclined at 600 to the
axis of major principal stress. What is the maximum intensity of shear stress in the
material at the point
14. It is required to design a closed coiled helical spring which shall deflect 1mm under
an axial load of 100 N at a shear stress of 90 Mpa. The spring is to be made of
round wire having shear modulus of 0.8 x 105 Mpa. The mean diameter of the coil
is 10 times that of the coil wire. Find the diameter and length of the wire.
15. A steel shaft ABCD having a total length of 2400 mm is contributed by three
different sections as follows. The portion AB is hollow having outside and inside
diameters 80 mm and 50 mm respectively, BC is solid and 80 mm diameter. CD is
also solid and 70 mm diameter. If the angle of twist is same for each section,
determine the length of each portion and the total angle of twist. Maximum
permissible shear stress is 50 Mpa and shear modulus 0.82 x 105 MPa
16. Three planks of each 50 x200 mm timber are built up to a symmetrical I section for
a beam. The maximum shear force over the beam is 4KN. Propose an alternate
rectangular section of the same material so that the maximum shear stress
developed is same in both sections. Assume then width of the section to be 2/3 of
the depth.
17. Obtained the deflection under the greater load for the beam shown in fig using the
conjugate beam method.
60 KN 120 KN
2m 3m 1m
18. A beam of uniform section 10 m long carries a udl of KN/m for the entire length
and a concentrated load of 10 KN at right end. The beam is freely supported at the
left end. Find the position of the second support so that the maximum bending
moment in the beam is as minimum as possible. Also compute the maximum
bending moment,